ðåôåðàòû
Ãëàâíàÿ

Ðåôåðàòû ïî àâèàöèè è êîñìîíàâòèêå

Ðåôåðàòû ïî àäìèíèñòðàòèâíîìó ïðàâó

Ðåôåðàòû ïî áåçîïàñíîñòè æèçíåäåÿòåëüíîñòè

Ðåôåðàòû ïî àðáèòðàæíîìó ïðîöåññó

Ðåôåðàòû ïî àðõèòåêòóðå

Ðåôåðàòû ïî àñòðîíîìèè

Ðåôåðàòû ïî áàíêîâñêîìó äåëó

Ðåôåðàòû ïî ñåêñîëîãèè

Ðåôåðàòû ïî èíôîðìàòèêå ïðîãðàììèðîâàíèþ

Ðåôåðàòû ïî áèîëîãèè

Ðåôåðàòû ïî ýêîíîìèêå

Ðåôåðàòû ïî ìîñêâîâåäåíèþ

Ðåôåðàòû ïî ýêîëîãèè

Êðàòêîå ñîäåðæàíèå ïðîèçâåäåíèé

Ðåôåðàòû ïî ôèçêóëüòóðå è ñïîðòó

Òîïèêè ïî àíãëèéñêîìó ÿçûêó

Ðåôåðàòû ïî ìàòåìàòèêå

Ðåôåðàòû ïî ìóçûêå

Îñòàëüíûå ðåôåðàòû

Ðåôåðàòû ïî áèðæåâîìó äåëó

Ðåôåðàòû ïî áîòàíèêå è ñåëüñêîìó õîçÿéñòâó

Ðåôåðàòû ïî áóõãàëòåðñêîìó ó÷åòó è àóäèòó

Ðåôåðàòû ïî âàëþòíûì îòíîøåíèÿì

Ðåôåðàòû ïî âåòåðèíàðèè

Ðåôåðàòû äëÿ âîåííîé êàôåäðû

Ðåôåðàòû ïî ãåîãðàôèè

Ðåôåðàòû ïî ãåîäåçèè

Ðåôåðàòû ïî ãåîëîãèè

Ðåôåðàòû ïî ãåîïîëèòèêå

Ðåôåðàòû ïî ãîñóäàðñòâó è ïðàâó

Ðåôåðàòû ïî ãðàæäàíñêîìó ïðàâó è ïðîöåññó

Ðåôåðàòû ïî êðåäèòîâàíèþ

Ðåôåðàòû ïî åñòåñòâîçíàíèþ

Ðåôåðàòû ïî èñòîðèè òåõíèêè

Ðåôåðàòû ïî æóðíàëèñòèêå

Ðåôåðàòû ïî çîîëîãèè

Ðåôåðàòû ïî èíâåñòèöèÿì

Ðåôåðàòû ïî èíôîðìàòèêå

Èñòîðè÷åñêèå ëè÷íîñòè

Ðåôåðàòû ïî êèáåðíåòèêå

Ðåôåðàòû ïî êîììóíèêàöèè è ñâÿçè

Ðåôåðàòû ïî êîñìåòîëîãèè

Ðåôåðàòû ïî êðèìèíàëèñòèêå

Ðåôåðàòû ïî êðèìèíîëîãèè

Ðåôåðàòû ïî íàóêå è òåõíèêå

Ðåôåðàòû ïî êóëèíàðèè

Ðåôåðàòû ïî êóëüòóðîëîãèè



Ðåôåðàòû ïî àâèàöèè è êîñìîíàâòèêå

Ðåôåðàòû ïî àäìèíèñòðàòèâíîìó ïðàâó

Ðåôåðàòû ïî áåçîïàñíîñòè æèçíåäåÿòåëüíîñòè

Ðåôåðàòû ïî àðáèòðàæíîìó ïðîöåññó

Ðåôåðàòû ïî àðõèòåêòóðå

Ðåôåðàòû ïî àñòðîíîìèè

Ðåôåðàòû ïî áàíêîâñêîìó äåëó

Ðåôåðàòû ïî ñåêñîëîãèè

Ðåôåðàòû ïî èíôîðìàòèêå ïðîãðàììèðîâàíèþ

Ðåôåðàòû ïî áèîëîãèè

Ðåôåðàòû ïî ýêîíîìèêå

Ðåôåðàòû ïî ìîñêâîâåäåíèþ

Ðåôåðàòû ïî ýêîëîãèè

Êðàòêîå ñîäåðæàíèå ïðîèçâåäåíèé

Ðåôåðàòû ïî ôèçêóëüòóðå è ñïîðòó

Òîïèêè ïî àíãëèéñêîìó ÿçûêó

Ðåôåðàòû ïî ìàòåìàòèêå

Ðåôåðàòû ïî ìóçûêå

Îñòàëüíûå ðåôåðàòû

Ðåôåðàòû ïî áèðæåâîìó äåëó

Ðåôåðàòû ïî áîòàíèêå è ñåëüñêîìó õîçÿéñòâó

Ðåôåðàòû ïî áóõãàëòåðñêîìó ó÷åòó è àóäèòó

Ðåôåðàòû ïî âàëþòíûì îòíîøåíèÿì

Ðåôåðàòû ïî âåòåðèíàðèè

Ðåôåðàòû äëÿ âîåííîé êàôåäðû

Ðåôåðàòû ïî ãåîãðàôèè

Ðåôåðàòû ïî ãåîäåçèè

Ðåôåðàòû ïî ãåîëîãèè

Ðåôåðàòû ïî ãåîïîëèòèêå

Ðåôåðàòû ïî ãîñóäàðñòâó è ïðàâó

Ðåôåðàòû ïî ãðàæäàíñêîìó ïðàâó è ïðîöåññó

Ðåôåðàòû ïî êðåäèòîâàíèþ

Ðåôåðàòû ïî åñòåñòâîçíàíèþ

Ðåôåðàòû ïî èñòîðèè òåõíèêè

Ðåôåðàòû ïî æóðíàëèñòèêå

Ðåôåðàòû ïî çîîëîãèè

Ðåôåðàòû ïî èíâåñòèöèÿì

Ðåôåðàòû ïî èíôîðìàòèêå

Èñòîðè÷åñêèå ëè÷íîñòè

Ðåôåðàòû ïî êèáåðíåòèêå

Ðåôåðàòû ïî êîììóíèêàöèè è ñâÿçè

Ðåôåðàòû ïî êîñìåòîëîãèè

Ðåôåðàòû ïî êðèìèíàëèñòèêå

Ðåôåðàòû ïî êðèìèíîëîãèè

Ðåôåðàòû ïî íàóêå è òåõíèêå

Ðåôåðàòû ïî êóëèíàðèè

Ðåôåðàòû ïî êóëüòóðîëîãèè

Êóðñîâàÿ ðàáîòà: Ðîçðàõóíîê ô³íàíñîâèõ ïîêàçíèê³â òà åêîíîì³÷íî¿ åôåêòèâíîñò³ ïåðåâåçåíü

Êóðñîâàÿ ðàáîòà: Ðîçðàõóíîê ô³íàíñîâèõ ïîêàçíèê³â òà åêîíîì³÷íî¿ åôåêòèâíîñò³ ïåðåâåçåíü

̲ͲÑÒÅÐÑÒÂÎ ÍÀÓÊÈ ÒÀ ÎѲÒÈ ÓÊÐÀ¯ÍÈ

ÃÎÐ˲ÂÑÜÊÈÉ ÒÅÕͲÊÓÌ ÄÎÍÅÖÜÊÎÃÎ

ÍÀÖ²ÎÍÀËÜÍÎÃÎ ÒÅÕͲ×ÍÎÃÎ ÓͲÂÅÐÑÈÒÅÒÓ

ÊÓÐÑÎÂÀ ÐÎÁÎÒÀ

ÎÏÏ.ÊÐ.01.0.00.00.ÏÇ

ÃÐÓÏÀ Å301

Áåðåçí³êåð Ìèêèòà Ìèõàéëîâè÷


2003 ð.


 

 

 

 

Ðîçðàõóíîê ô³íàíñîâèõ ïîêàçíèê³â

òà åêîíîì³÷íî¿ åôåêòèâíîñò³

ïåðåâåçåíü

 

 

Ïîÿñíþâàëüíà çàïèñêà

ÎÏÏ ÊР  00.00.00.ÏÇ

 

 

 

 

 

 

 

 

Êåð³âíèê ïðîåêòó

       ×óáîâñüêà Í.À.

Ðîçðîáèâ ñòóäåíò
 

     Áåðåçí³êåð Ì.Ì.

2003 ð.


̲ͲÑÒÅÐÑÒÂÎ ÍÀÓÊÈ ÒÀ ÎѲÒÈ ÓÊÐÀ¯ÍÈ

ÃÎÐ˲ÂÑÜÊÈÉ ÒÅÕͲÊÓÌ ÄÎÍÅÖÜÊÎÃÎ

ÍÀÖ²ÎÍÀËÜÍÎÃÎ ÒÅÕͲ×ÍÎÃÎ ÓͲÂÅÐÑÈÒÅÒÓ

 

ÇÀÂÄÀÍÍß

ÍÀ ÊÓÐÑÎÂÅ ÏÐÎÅÊÒÓÂÀÍÍß ÏÎ ÏÐÅÄÌÅÒÓ

“ÅÊÎÍÎ̲ÊÀ, ÎÐÃÀͲÇÀÖ²ß ÒÀ ÏËÀÍÓÂÀÍÍß ÀÂÒÎÌÎÁ²ËÜÍÎÃÎ ÒÐÀÍÑÏÎÐÒÓ”

Ñòóäåíòà ãðóïè Å402_____


Íà çàâäàííÿ: ___________   

 

²ñõîäíà ³íôîðìàö³ÿ.

ÏÎÊÀÇÍÈÊÈ

ÓÌ.ÏÎÇÍ.

ÇÍÀ×ÅÍÍß.

Ìàðêà ðóõîìîãî ñêëàäó.

Êàìàç -5320

ʳëüê³ñòü àâòîìîá³ë³â.

À³

12

Ãîäèíè ïðàö³, ãîä.

Òí

12,3

Êîåô³ö³åíòè âèêîíàííÿ:

Âàíòàæîì³ñòêîñò³

Ïðîá³ãó

Ïàðêó

g 1

25

Lâ.ã

21

1 .ÂÈÐÎÁÍÈ×À ÏÐÎÃÐÀÌÀ Ç ÅÊÑÏËÓÀÒÀÖ²¯

ÐÓÕÎÌÎÃÎ ÑÊËÀÄÓ ÂÀÍÒÀÆÍÎÃÎ ÏÀÐÊÓ

Òàáëèöÿ 1.1. Òåõí³÷íà õàðàêòåðèñòèêà àâòîìîá³ëÿ
Íàéìåíóâàííÿ ïîêàçíèêà   Çíà÷åííÿ
1. Çàâîä âèãîòîâëþâà÷ Êàìñêèé àâò. Çàâîä
 2. Âàíòàæîï³äéîìí³ñòü 8
 3.  Ðîçì³ð àâòîìîá³ëþ(ãàáàðèòè)
äëèíà 7435
øèðèíà 2500
âûñîòà 2530
 4. Ðîçì³ð øèí 260R-508
5. Ìàðêà ïàëèâà ÄÒ
 6.  Òèï äâèãóíà ÊàìÀÇ-740Ä
 7. Ïîòóæí³ñòü äâèãóíà 210 ë.ñ.

1.1.    Ðîçðàõóíîê ïîêàçíèê³â ðîáîòè àâòîìîá³ëÿ çà äåíü.                   

                                  

1.1.1. ʳëüê³ñòü ¿çäîê.                                 

                                                           7(¿çä)  

äå:                              

Òí - ÷àñ â íàðÿä³                               

β - êîåô³ö³ºíò âèêîðèñòàííÿ ïðîá³ãó                               

Vò- øâèäê³ñòü òåõí³÷íà                              

l â¿ - äîâæèíà âàíòàæíî¿ ¿çäêè                               

t í-ð - ÷àñ íàâàíòàæåííÿ-ðîçâàíòàæåííÿ                           

                                  

           

1.1.2. Îáñÿã ïåðåâåçåíü ó òîííàõ

                                  

Qäåí=qí*γ*Z¿=56,00(ò)

äå:

γ - êîåô³ö³ºíò âèêîðèñòàííÿ âàíòàæîï³äéîìíîñò³

                       

1.1.3. Îáñÿã ïåðåâåçåíü ó òîíî-ê³ëîìåòðàõ:

                                  

Ðäåí=Qäåí*γ*Z¿=1176,00(ò.êì)

                       

1.1.4. Äîáîâèé ïðîá³ã

                                  

Läîá=  lâ¿*Z¿  =229,7(êì)                   

                 β                           

1.1.5. Íàâàíòàæåíèé ïðîá³ã çà äåíü

                                  

Lâ=Läîá*β =    147(êì)

                       

1.2. Âèðîáíè÷à ïðîãðàìà ïàðêó ðóõîìîãî ñêëàäó

1.2.1. Àâòîìîá³ëå äí³ â ãîñïîäàðñòâ³ çà ð³ê

                                  

ÀÄã=À³*Äê=   4380(àâòî-äí³)                      

äå:                              

À³ - îáë³êîâà ê³ëüê³ñòü àâòîìîá³ë³â                                  

                                  

1.2.2. Àâòîìîá³ëå äí³ â åêñïëóàòàö³¿

                                  

ÀÄð=ÀÄã*αâ=3175,5(àâòî-äí³)       

           

1.2.3. Îáñÿã ïåðåâåçåíü ó òîíàõ çà ð³ê

                                  

Qp=Qäåí*Àäð=177828(ò)

                       

1.2.4. Îáñÿã ïåðåâåçåíü ó òîíî-ê³ëîìåòðàõ çà ð³ê

                       

Pp = Ðäåí * ÀÄð=         3734388(ò.êì)

                       

1.2.5. Çàãàëüíèé ïðîá³ã çà ð³ê

                                  

Lçàã = Läîá * ÀÄð=      729412,35(êì)

                       

1.2.6. Íàâàíòàæåíèé ïðîá³ã çà ð³ê

                       

Lâ.ð = Lâ * ÀÄð=466798,5(êì)

                       

1.2.7. г÷íà ê³ëüê³ñòü ¿çäîê

                                  

Z¿ð = Z¿* ÀÄð=22229(¿çä)

                       

1.2.8. Àâòîìîá³ëå ãîäèíè â åêñïëóàòàö³¿ çà ð³ê              

                                  

ÀÃåð=  Òí*ÀÄð=39058,7(àâòî-ã)

                       

1.2.9. Àâòîìîá³ëå ãîäèíè ïðîñòîþ ï³ä íàâàíòàæåííÿì-ðîçâàíòàæåííÿì çà ð³ê

                       

ÀÃïð.ð=tí-ð*ÀÄð* Z¿=10447,4(àâòî-ã)

                       

1.2.10. Àâòîìîá³ëå ãîäèíè ó ðóñ³ çà ð³ê

                       

ÀÃðóõ.ð= Àãåð- ÀÃïð.ð=28611,3(àâòî-ã)


2. ÂÈÐÎÁÍÈ×À ÏÐÎÃÐÀÌÀ Ç ÒÅÕͲ×ÍÎÃÎ ÎÁÑËÓÃÎÂÓÂÀÍÍß ² ÐÅÌÎÍÒÓ ÐÓÕÎÌÎÃΠ    ÑÊËÀÄÓ

Òàáëèöÿ 2.1. Íîðìàòèâí³ äàí³

Íàéìåíóâàííÿ çíà÷åíü

Óìîâí³ ïîçíà÷êè

Ïîêàçíèêè

1. Ïðîá³ã àâòîìîá³ëÿ äî
êàï³òàëüíîãî ðåìîíòó

Lêð

300000
2. Ïðîá³ã äî ïåðøîãî òåõí³÷íîãî
 îáñëóãîâóâàííÿ

Lòî-1

4000
3. Ïðîá³ã äî äðóãîãî òåõí³÷íîãî
îáñëóãîâóâàííÿ

Lòî-2

12000
4. Òðóäîì³ñòê³ñòü ïåðøîãî
òåõí³÷íîãî îáñëóãîâóâàííÿ

tòî-1

1,91
5. Òðóäîì³ñòê³ñòü äðóãîãî
òåõí³÷íîãî îáñëóãîâóâàííÿ

tòî-2

8,63
6. Òðóäîì³ñòê³ñòü ùîäåííîãî
îáñëóãîâóâàííÿ

tùî

0,75
7. Òðóäîì³ñòê³ñòü ïîòî÷íîãî
ðåìîíòó

tïð

6,7

                                                                                                                     

2.1.  Ðîçðàõóíîê ê³ëüêîñò³ âïëèâ³â

                                              

2.1.1. ʳëüê³ñòü êàï³òàëüíèõ ðåìîíò³â

                                              

Nêð =  Lçàã  =2

            Lêð

2.1.2. ʳëüê³ñòü ÒÎ-2

                                              

Nòî-2     =  Lçàã  - -  Nêð = 59

                Lòî-2

2.1.3. ʳëüê³ñòü TO-I

                                  

Nòî-1 =   Lçàã  - -  (Nêð+Nòî-2) = 121

                Lòî-2                                

2.1.4. ʳëüê³ñòü ÙΠ

                                  

Nùî = Lçàã        =3176

            Läîá

2.2.    Òðóäîì³ñòê³ñòü îáñëóãîâóâàíü                                          

2.2.1. Òðóäîì³ñòê³ñòü ÙΠ  

                                  

Òùî = Nùî*tùî = 2382 (÷îë-ã)

2.2.2. Òðóäîì³ñòê³ñòü TO-I  

                                  

Òòî-1 = tòî-1*Nòî-1 = 231,1 (÷îë-ã)

2.2.3. Òðóäîì³ñòê³ñòü ÒÎ-2 

                                  

Òòî-2     =  tòî-2*Nòî-2 =509,2(÷îë-ã)

2.2.4. Òðóäîì³ñòê³ñòü ÏÐ

                                              

Òïð = tïð*Lçàã/1000 = 4887,1(÷îë-ã)

2.2.5. Çàãàëüíà òðóäîì³ñòê³ñòü

                                              

Òçàã = Òùî+Òòî-1+Òòî-2 +Òïð = 8009,4 (÷îë-ã)  


3.×ÈÑÅËÜͲÑÒÜ ÏÅÐÑÎÍÀËÓ                                      

                                                                      

3.1. ×èñåëüí³ñòü âî䳿⠠                                                                

Nâ =   1,05*ÀÃå =23(÷îë.)  

           ÔÐ×*Êïò                                                                   

äå:

1,05   - êîåô³ö³ºíò, ùî âðàõîâóº ï³äãîòîâ÷î-çàêëþ÷íèé ÷àñ;                                                  

Êïò- êîåô³ö³ºíò, ùî âðàõîâóº ïðîäóêòèâí³ñòü ïðàö³, ( Êïò = 1.05)

ÔÐ×1â - ôîíä ðîáî÷îãî ÷àñó,ãîä                                                             

ÔÐ×1â = (Äê - Äâ³äï - Äñâ – Ääåðæ.îáîâ - Äõâîð - Äâèõ) * Òð.ä- Äïñ * t1=1695 (ã)                                  

äå:                                                                 

Äâ³äï -      äí³ â³äïóñòêè [ùîð³÷íà äîäàòêîâà â³äïóñòêà âñòàíîâëåíà òðèâàë³ñòþ 24 êàëåíäàðíèõ äí³ äëÿ âñ³õ ïðàöþþ÷èõ ÀÒÏ,                                                              

äëÿ âî䳿â âñòàíîâëþºòüñÿ ùå äîäàòêîâà ùîð³÷íà â³äïóñòêà çà îñîáëèâèé õàðàêòåð ðîáîòè,ÿêà âñòàíîâëåíà â³ä 4 äî 7 êàëåíäàðíèõ äí³â (çã³äíî óìîâ,âèçíà÷íèõ ó Êîëåêòèâíîìó äîãîâîð³ ÀÒÏ)                                                                  

Äñâ                - äí³ ñâÿòêîâ³ ïåâíîãî ðîêó;                                                            

Ääåðæ.îáîâ  - äí³ íåÿâêè íà ðîáîòó â çâ'ÿçêó ç âèêîíàííÿì äåðæàâíèõ îáîâ'ÿçê³â, (3äí)

Äõâîð            - äí³ íåÿâêè íà ðîáîòó ç ÷è õâîðîáè ³íøèõ ïîâàæíèõ ïðè÷èí, Äõâîð = 5 äí.; 

Äâèõ              - äí³ âèõ³äí³ ïåâíîãî ðîêó;                                                              

Tp ä                - íîðìàòèâíà òðèâàë³ñòü ðîáî÷îãî äíÿ,ãîä (8 ãîä.)                         

t1                    - ÷àñ çì³íè íà ÿêèé ñêîðî÷åíèé ðîáî÷èé äåíü ó ñâÿòêîâ³ äí³, ti = 1 ì;            

Äïñ                 - äí³ ïåðåäñâÿòêîâ³ ïåâíîãî ðîêó.                                                             

3.2. ×èñåëüí³ñòü ðåìîíòíèê³â                                                                 

Nð.ð.=         Tçàã            =  4(÷îë)

                ÔÐ×ð*Êïò

           

ÔÐ×ð=  (Äê – Äâ³äï.ð - Äñâ – Ääåðæ.îáîâ - Äõâîð - Äâèõ) * Òð.ä- Äïñ * t1=1743

           

3.3. ×èñåëüí³ñòü äîïîì³æíèõ ðîá³òíèê³â                                                          

Νäîï. = 0,2 * Νρ.ρ. = 1 (÷îë),                                                             

äå:                                                                 

0,2 - 20% â³ä ÷èñåëüíîñò³ ðåìîíòíèê³â                                                                                      

3.4. ×èñåëüí³ñòü êåð³âíèê³â ³ ñïåö³àë³ñò³â:                                                                     

Nêep = (Nâ + Näîï +Νρ,ρ.) * 0,1 = 3 (÷îë)                                                                 

                                                                      

äå:                                                                 

0,1 - 10% â³ä ñóìè ê³ëüêîñò³ âî䳿â, ðåìîíòíèê ³ äîïîì³æíèõ                                                             

ðîá³òíèê³â                                                               

3.5. ×èñåëüí³ñòü ïåðñîíàëó ÀÒÏ                                                 

                                                          

Nïep = Nâ+ Np.p + Νκ+Näîï + Nêep =31 (÷îë)                                               


4.ÂÈÒÐÀÒÈ ÍÀ ÎÏËÀÒÓ ÏÐÀÖ²                                                                     

                                                                                                                                

4.1.Îñíîâíà çàðîá³òíà ïëàòà âî䳿â, ùî ïðàöþþòü â³äðÿäíî.                                                                                                                              

                                                                                                                                

4.1.1. ³äðÿäíà çàðîá³òíà ïëàòà âî䳿â âàíòàæíèõ àâòîìîá³ë³â:           

ÎÔÇÏ â = (Qp * Ñò + Pp * Cò.êì) * Êâ + ÀÃï-ç * Ñãîä = 74544,4 (ãðí.)

äå:

Ñãîä      - òàðèôíà ãîäèííà ñòàâêà âîä³ÿ III êëàñó (1,684ãðí)                                                    

Êâ         - êîåô³ö³ºíò, ùî âðàõîâóº êëàñ âàíòàæó (1,0)

ÀÃï-ç    - àâòîìîá³ë³ ãîäèíè ï³äãîòîâ÷î-çàêëþ÷í³,                                                                     

Ñò.êì            - â³äðÿäíà ðîçö³íêà çà 1 òîíî-ê³ëîìåòð.

                                                                      

ÀÃï-ç = 0,05 * ÀÃå = 1952,9  (àâòî-ã),

                                                                                             

äå:                                                                                                                                                   

0,05    - 5% â³ä àâòîìîá³ëå ãîäèí â åêñïëóàòàö³¿;                                               

Ñò      - â³äðÿäíà ðîçö³íêà çà îäíó òîíó ïåðåâåçåíîãî âàíòàæó;

                                  

Cò =  Ñãîä * Í÷àñò /60 = 0,0017   (ãðí)

Ñò.êì     =Ñãîä*Í÷àñ.ò.êì  =  0,019 (ãðí)

äå:     Í÷àñ.ò       - íîðìà ÷àñó çà òîíó ïåðåâåçåíîãî âàíòàæó;

          Íâð.ò.êì   - íîðìà ÷àñó çà 1òîíî-ê³ëîìåòð;     

Í÷àñ.ò  =     tí-ð    =  0,06 (ð³ê)                                                                                                                                 qí* γ

                                   1

Íâð.ò.êì  =                                     =  0,011

                      Vòð* βð*qí* γ

4.2. Äîäàòêîâà çàðîá³òíà ïëàòà

4.2. 1 . Íàäáàâêà çà êëàñí³ñòü :                                                                             

                                                                                 

Hêë = Ñãîä * ÔÐ×1â (0,25*Νâ² + 0,1 * Nâ²²) = 7564,1 (ãðí)                                                                           

äå:   Νâ² , Nâ²²  - ÷èñåëüí³ñòü âî䳿â â³äïîâ³äíî ² ³ II êëàñ³â;                                                                                                                                     

0,25 - 25% - äîïëàòà âîä³ÿì ² êëàñó;                                                                    

0, 1 - 1 0% - äîïëàòà âîä³ÿì II êëàñó;                                                                  

                                                                      

Νâ² = Nâ *ಠ  = 7 (÷îë.)                                                                

Νâ²² =            Nâ *ಲ = 9 (÷îë.)

           

à³, àö - â³äñîòîê âî䳿â â³äïîâ³äíî ² ³ II êëàñ³â,                                                              

à²=30%,ಲ=40%

4.2.2. Ïðåì³ÿ âîä³ÿì âàíòàæíèõ àâòîìîá³ë³â çà ñâîº÷àñíå ³ ÿê³ñíå âèêîíàííÿ çàâäàíü:                                                                                                                            

Ï = àïð * ÎÔÇÏ â /100 = 22363,3 (ãðí.)

äå:      

àïð - â³äñîòîê ïðå쳿 30%

4.3. Äîïëàòà çà êåð³âíèöòâî áðèãàäîþ

Äáð = ÔÐ× * Ñãîä * Ν6ρ * Êáð = 1712,6 (ãðí)                                                         

äå:                                                     

Ν6ρ - ê³ëüê³ñòü áðèãàä;                                                      

                                                          

Ν6ρ =   Nâ   =  3

            náð

                                              

náð=8                                                                                                            

äå:                                                                                                                

náð - ê³ëüê³ñòü ëþäèí ó áðèãàä³,                                                                                                   

Êáð-êîåô³ö³ºíò,âðàõîâóþ÷èé äîïëàòó çà êåð³âíèöòâî áðèãàäîþ â çàëåæíîñò³ â³ä ÷èñåëüíîñò³ âî䳿â ó áðèãàä³ (0,2)

4.4. Äîïëàòà çà ðîáîòó ó âå÷³ðí³é òà í³÷íèé ÷àñ                                                            

                                                                      

Äâ-í. = Ñãîä*(0,2 * ÀÃâ + 0,4 * ÀÃí)= 8556,1  (ãðí)                                                           

äå:                                                                                                                            

ÀÃâ, ÀÃí - àâòîìîá³ëå ãîäèíè ðîáîòè â³äïîâ³äíî ó âå÷³ðí³é ³   í³÷íèé ÷àñ                                       

ÀÃÂ= tâ * ÀÄð= 12702 (àâòî-ã)                                                                 

                                                                      

ÀÃÍ = tí * ÀÄð= 6351 (àâòî-ã)                                                                                         

äå:                                                                                                                                       

tâ,tí    - ê³ëüê³ñòü ãîäèí, â³äïðàöüîâàíèõ â³äïîâ³äíî ó    âå÷³ðí³é ³ í³÷íèé ÷àñ,         

tâ = 4  

tí = 2  

0,2    - 20% - â³äñîòîê äîïëàòè çà ðîáîòó ó âå÷³ðí³é ÷àñ,                                                                      

0,4    - 40% - â³äñîòîê äîïëàòè çà ðîáîòè â í³÷íèé ÷àñ.                                                            

                                                                      

4.2.6. Äîïëàòà çà åêñïåäóâàííÿ âàíòàæó                                                            

                                                                      

Äåêñ =aåêñ * ÇÏïîã = 6906,4 (ãðí)                                                                                                                                        

äå:àåêñ - â³äñîòîê çà åêñïåäèðóâàííÿ âàíòàæó â³ä ïîãîäèííî¿ çàðîá³òíî¿ ïëàòè:                                                                   

-äëÿ âàíòàæ³â,ÿê³ íå ïîòðåáóþòü áàãàòî ÷àñó íà ïðèéìàííÿ, çäà÷ó ³ îôîðìëåííÿ äîêóìåíò³â- 10%;                                                                                                                              

ÇÏïîã - ïîãîäèííà çàðîá³òíà ïëàòà.

                                                                      

ÇÏïîã = 1,05 * AÃe * Ñãîä = 69063,6 (ãðí)                                                          


4.2.7. Äîïëàòà çà ó÷àñòü ó íàâàíòàæíî-ðîçâàíòàæóâàëüíèõ ðîáîòàõ                                                 

                                                          

Äí-ð = àí-ð * ÇÏòàð=10359,5 (ãðí)                                                     

äå:                                                                                                                

àí-ð - â³äñîòîê äîïëàòè çà ó÷àñòü ó íàâàíòàæíî-   ðîçâàíòàæóâàëüíèõ ðîáîòàõ(15%)

4.2.9. Ñóìà íàäáàâîê ,äîïëàò ³ ïðåì³é:                                                               

                                                                      

ΣÍÄÏ=Íêë+Äáð+Äåêñ+Äñâ+Äí-ð+Ï+Äâí=57462 (ãðí)                                                        

                                                                      

4.2. ²Î.Ãàðàíò³éí³ òà êîìïåíñàö³éí³ âèïëàòè:

                                                                      

ÃÊÂ=(ÎÔÇÏ â +Σ ÍÄÏ)*Ïãêâ/100 = 14784,7 (ãðí)

                                                                      

äå: Ïãêâ-â³äñîòîê ãàðàíò³éíèõ òà êîìïåíñàö³éíèõ âèïëàò;                                                                  

Ïãêâ= (Äâ³ä/Äê-Äñâ-Äâèõ-Äâ³ä)* ² 00+1 , 1 =11,2%

äå:Äâ³ä-òðèâàë³ñòü â³äïóñòêè ó ðîáî÷èõ äíÿõ äëÿ âî䳿â:                                                          

â³ä Ç,0ò ³ âèùå-23 äí³

Äâèõ-ê³ëüê³ñòü âèõ³äíèõ äí³â çà ïåâíèé ð³ê.(104)                                                        

4.2. 1 1 Ôîíä äîäàòêîâî¿ çàðîá³òíî¿ ïëàòè:

                                                                      

ÄÔÇÏâ = ÃÊÂ+ ΣÍÄÏ = 72246,7 (ãðí)                                                               

                                                                      

4.3.3àãàëüíèé ôîíä çàðîá³òíî¿ ïëàòè âî䳿â:

                                                                      

ÇÔÇÏâ=ÎÔÇÏâ+ÄÔÇÏâ = 146791,1 (ãðí)

4.4. Ñåðåäíüîì³ñÿ÷íà çàðîá³òíà ïëàòà âî䳿⠠                                                               

                                                                      

ÇÏñåð.ì =  ÇÔÇÏâ  = 531,9 (ãðí.)                                                                 

                   Nâ*nìic                                                               

                                                                      

äå:     nì³ñ.- ê³ëüê³ñòü ì³ñÿö³â ó ðîö³, nì³ñ =12

4.5.Âèïëàòè ç ôîíäó ìàòåð³àëüíîãî çàîõî÷óâàííÿ:                                                                  

                                                                      

Âìç=àìç*ÇÔÇÏâ/100=29358,2 (ãðí)                                                            

                                                                      

äå: àìç-ðîçì³ð âèïëàò ç ôîíäó ìàòåð³àëüíîãî çàîõî÷óâàííÿ(20%)                                                                                                                            

4.6. Çàãàëüíèé ôîíä çàðîá³òíî¿ ïëàòè âî䳿â ç óðàõóâàííÿì âèïëàò ç ôîíäó ìàòåð³àëüíîãî çàîõî÷óâàííÿ:                                                                      

                                                                      

ÇÔÇÏìç= ÇÔÇÏâ+Âìç=176149,3 (ãðí)

4.7.³äðàõóâàííÿ ç ôîíäó îïëàòè ïðàö³ âî䳿â:

                                                                      

4.7.1. Ó ïåíñ³éíèé ôîíä                                                               

                                                                      

Bï.ô. =ÇÔÇÏìç* àïô=56367,8 (ãðí)                                                             

äå: àïô - ðîçì³ð â³äðàõóâàíü ó ïåíñ³éíèé ôîíä, àïô = 32%,                                                                 

4.7.2 Â ôîíä çàéíÿòîñò³                                                                 

                                                                      

Âô.ç. = ÇÔÇÏìç* àôç = 3699,1 (ãðí)                                                             

äå: àôç - ðîçì³ð â³äðàõóâàíü ó ôîíä çàéíÿòîñò³, àôç - 2,1%                                                                    

                                                                      

4.7.3. Ó ôîíä ñîö³àëüíîãî ñòðàõóâàííÿ                                                              

                                                                      

Âñ.ñ= ÇÔÇÏìç* Çñ.ñ = 5108,3 (ãðí)                                                                                                                                      

äå: Çñ ñ - ðîçì³ð â³äðàõóâàíü ó ñîö³àëüíîãî ñòðàõóâàííÿ, Çñ ñ =2,9%                                                                

4.7.4. Ó ôîíä íåùàñíèõ âèïàäê³â                                                            

                                                                      

Âí.â=ÇÔÇÏìç*àíâ=2888,8 (ãðí)                                                             

äå: àí.â. - ðîçì³ð â³äðàõóâàíü ó ôîíä íåùàñíèõ âèïàäê³â, àí.â. = 1,64%                                                                                                     

4.7.5. ³äðàõóâàííÿ íà ñîö³àëüí³ çàõîäè                                                             

                                                                      

Âñ.3 = Âï.ô. + Âô.3. + Âñ.ñ + Âí.â =68064 (ãðí)                                                         

4.8.Çàãàëüíèé ôîíä çàðîá³òíî¿ ïëàòè ðåìîíòíèõ ðîá³òíèê³â:                                                             

ÇÔÇÏ ð.ð.=Lçàã*Íçï.*Êäîä*Êìç*Êñç/1000 = 9512,7 ãðí                                                                   

äå:Íçï-íîðìà âèòðàò íà çàðîá³òíó ïëàòó ðåìîíòíèõ ðîá³òíèê³â 1000 KM ïðîá³ãó(5,72 ãðí

Êäîä.-êîåô³ö³ºíò,ÿêèé âðàõîâóº äîäàòêîâó çàðîá³òíó ïëàòó ðåìîíòíèõ ðîá³òíèê³â(1,9)       

K ìç-êîåô³ö³ºíò,ÿêèé âðàõîâóº âèïëàòè ç ÔÌÇ (1,2)

Êñç = 1,3864                                                  

4.10.3àãàëüíà çàðîá³òíà ïëàòà êåð³âíèê³â ³ ñïåö³àë³ñò³â:                                                          

                                                          

ÇÔÇÏ êåð.=Íêåð*Ìïî*Êñç*nì = 13974,9(ãðí.)                                                         

                                                          

äå : Ìïî-ì³ñÿ÷íèé ïîñàäîâèé îêëàä (280 ãðí)

nì-ê³ëüê³ñòü ì³ñÿö³â ïåðåâåçåíü (12)

Êñç=1,3864

4.11. Çàðîá³òíà ïëàòà äîïîì³æíèõ ðîá³òíèê³â:                                                  

                                                          

ÇÏ äîï= Ìäîï*Ìïî*Êñç*Ïì=3327,36 (ãðí.)                                                                                                                                                                                                                                  


5. ÌÀÒÅвÀËÜͲ ÂÈÒÐÀÒÈ

5.1 .Âèòðàòè íà ïàëèâî                                                                 

5.1.1. Åêñïëóàòàö³éí³ âèòðàòè ïàëèâà

                                                                      

Òåêñ =     Lçàã*Íêì + Ðð*Íò.êì = 230900,1

                  100             100

                                                                      

äå: HKM  - ë³í³éíà íîðìà ïàëèâà íà 100 KM ïðîá³ãó (25ë)

Íò.êì - ïèòîìà íîðìà âèòðàòè ïàëèâà íà 100 òêì:                                                                     

äëÿ àâòîìîá³ë³â ç äèçåëüíèì-1,3 ë.

5.2. Íàäáàâêè äî âèòðàò ïàëèâà:                                                             

Òíàä = Òåêñ * àíàä/100 = 6003,4 (ë)                                                                

äå: àíàä - â³äñîòîê íàäáàâêè: çà ðîáîòó ó çèìîâèé ïåð³îä-2,1%;                                            

âíóòð³øíüî ãàðàæí³ íóæäè – 0,5%

5.3. Çàãàëüí³ âèòðàòè ïàëèâà                                                                    

                        Òçàã = Òåêñ+ Òíàä =236903   (ë)

5.4. Åêîíîì³ÿ ïàëèâà                                                                     

Òåêîí=Òçàã* àåêîí = 11845,2(ë)

äå: àåêîí - â³äñîòîê åêîíî쳿(5%).                                                                                   

5.5. Ïàëèâî ç óðàõóâàííÿì åêîíî쳿 ó ë³òðàõ:                                                               

Òåë = Òçàã-Òåêîí = 225058,3(ë)

 5.6. Âàðò³ñòü çåêîíîìëåíîãî ïàëèâà                                                                   

Ñåê = Òåêîí*Ö1ë = 18952,32 (ãðí)

äå: Ö ²ë - ö³íà îäíîãî ë³òðà ïàëèâà (1,50 ãðí.)

5.7. Âàðò³ñòü ïàëèâà                                                           

Ñò = Òåë*Ö1ë = 360093,33 (ãðí)

5.8. Ïðåì³ÿ çà åêîíîì³þ ïàëèâà                                                               

Ïò= 0,8* Ñåê = 15161,86 (ãðí)                                                                    

äå: 0,8 - 80% - â³äñîòîê ïðå쳿 çà åêîíîì³þ ïàëèâà                                                                   

5.9. Âèòðàòè íà ïàëèâà, ùî âêëþ÷àþòüñÿ â ñîá³âàðò³ñòü ïåðåâåçåíü                                     

Bn = Ñò + Ïò = 375255,2 (ãðí)

5.10. Âèòðàòè íà ìàñòèëüí³ ìàòåð³àëè                                                                

5.10.1. Âèòðàòè íà ìàñëî äëÿ äâèãóí³â                                                               

    Âì.ä  =   Ò çàã* Í ì.ä.*d ì.ä.*Ö1ò  = 22088,9(ãðí)   

                             100*1000

äå:Íì.ä - íîðìà âèòðàòè ìàñëà äëÿ äâèãóíà íà 100 ë âèòðàòè ïàëèâà (2,8ë)               

dì.ä- ïèòîìà âàãà ìàñëà (0,9)

Ö1ò - ö³íà îäí³º¿ òîíè ìàñëà, (3700 ãðí/ò).

                                                                      

5.10.2. Âèòðàòè íà òðàíñì³ñ³éíå ìàñëî:

                                                                      

    Âòð  =   Ò çàã* Í òð*d òð*Ö1ò  = 2155,8 (ãðí)   

                              100*1000                                                           

äå:                                                                 

Í òð  - íîðìà âèòðàòè òðàíñì³ñ³éíîãî ìàñëà íà 100 ë âèòðàòè                                                 

ïàëèâà (0,4 ë ),                                                                                                                              

d òð  - ïèòîìà âàãà òðàíñì³ñ³éíîãî ìàñëà (0,91);                                     

Ö 1ò - ö³íà îäí³º¿ òîíè òðàíñì³ñ³éíî¿ ìàñëà, (2500 ãðí.) 

5.10.3. Âèòðàòè íà ïëàñòè÷í³ ìàñòèëà

                                                                      

Âïë  =   Ò çàã* Í ïë *Ö1ò  = 2321,7 (ãðí)   

                  100*1000

                                                                                 

äå:Íïë - íîðìà âèòðàòè ïëàñòè÷íîãî ìàñòèëà íà 100ë âèòðàòè                                               

ïàëèâà (0,35)

Ö1ò - ö³íà îäí³º¿ òîíè ïëàñòè÷íîãî çìàùåííÿ (2800 ãðí/ò)                                                      

5.10.4. Âèòðàòè íà ñïåö³àëüí³ ìàñëà:

                                                                      

Âñï  =   Ò çàã* Í ñï * d *Ö1ò  = 993,9 (ãðí)   

                    100*1000

                                                                      

ãäå:Íñï - íîðìà âèòðàòè ñïåö³àëüíîãî ìàñëà íà 100ë âèòðàòè ïàëèâà (0,15)   ,                      

(dcï- ïèòîìà âàãà ñïåö³àëüíèõ ìàñåë (0,92 ã/ñì)                                     

Ö1ò - ö³íà îäí³º¿ òîíè ñïåö³àëüíîãî ìàñëà(3040 ãðí/ò).

5.10.5. Âèòðàòè íà ãàñ                                                                   

Âêåð  =   Ò çàã*ρ *0,5 *Ö1ò  = 1308,9 (ãðí)   

                        100*1000

äå-    ð-ïèòîìà âàãà ïàëèâà:äëÿ äèçåëüíîãî ïàëèâà-0,85 ã/ñì .                                                

Ö1ò — ö³íà îäí³º¿ òîííè ãàñó, (1300ãðí).                                                            

5.10.6. Âèòðàòè íà îáòèðàëüí³ ìàòåð³àëè 

                                                          

Âîáò=Àå*Íîáò*Ö1êã = 1044 (ãðí)

äå: Aå   - ê³ëüê³ñòü àâòîìîá³ë³â â åêñïëóàòàö³¿,                                                               

Ae = A³ * αâ = 8,7 (àâò.)                                                                  

Hîáò - íîðìà îáòèðàëüíèõ ìàòåð³àë³â íà îäèí àâòîìîá³ëü:                                                       

äëÿ âàíòàæíèõ à/ì-24 êã;                                                  

Ö1êã — ö³íà îäíîãî ê³ëîãðàìà îáòèðàëüíèõ ìàòåð³àë³â (5 ãðí).                                              

5.10.7. Âèòðàòè íà ³íø³ åêñïëóàòàö³éí³ ìàòåð³àëè                                                                    

³íø = À³ * ͳíø = 180 (ãðí)

äå: ͳíø³ - íîðìà âèòðàò íà ³íø³ åêñïëóàòàö³éí³ ìàòåð³àëè(15 ãðí)                                                                

5.10.8. Çàãàëüí³ âèòðàòè íà ìàñòèëüí³ ìàòåð³àëè

                                                          

Âìì.çàã =  Âì.ä + Âòð + Âïë + Âñï + Âêåð + Âîáò + ³íø³ = 30093,2 (ãðí)

5.10.9. Åêîíîì³ÿ âèòðàò íà ìàñòèëüí³ ìàòåð³àëè                                                           

Åñì = àå*Âìì.çàã =         1504,7 (ãðí)

äå: àå - â³äñîòîê åêîíî쳿 ìàñòèëüíèõ ìàòåð³àë³â(5%)                                                               

                                                                      

5.10.10. Ïðåì³ÿ çà åêîíîì³þ ìàñòèëüíèõ ìàòåð³àë³â                                                                

Ïñì = àï * Åñì = 1203,8 (ãðí),                                                         

äå: àï — â³äñîòîê ïðå쳿 çà åêîíîì³þ ìàñòèëüíèõ ìàòåð³àë³â(80%)

                                              

5.10.11. Âèòðàòè íà ìàñòèëüí³ ìàòåð³àëè ç óðàõóâàííÿì åêîíî쳿 ³ ïðå쳿

                                  

Âìì = Âììçàã - Åñì + Ïñì = 29792,3 (ãðí)

5.11. Âèòðàòè íà ðåìîíò òà â³äíîâëåííÿ çíîñó àâòîìîá³ëüíèõ øèí                                                                    

5.11.1. Âèòðàòè íà ðåìîíò òà â³äíîâëåííÿ çíîñó øèí äëÿ îäèíî÷íèõ àâòîìîá³ë³â.                                                            

Ñø =  Lçàã*Íø*nê*Ö1ê*Êòð  = 32736 (ãðí)

                    1000*100

äå:Íø - íîðìà íà â³äíîâëåííÿ çíîñó ³ ðåìîíò àâòîìîá³ëüíèõ øèí ó % â³ä âàðòîñò³ øèíè íà 1000 KM ïðîá³ãó (0,85) 

ïê- ê³ëüê³ñòü êîìïëåêò³â øèí íà îäíîìó àâòîìîá³ë³ áåç çàïàñíîãî êîëåñà (10);                    

Êòð - êîåô³ö³ºíò, ùî âðàõîâóº äîñòàâêó øèí íà ï³äïðèºìñòâî (1,1);

Ö1ê - ö³íà îäíîãî êîìïëåêòó øèí (480 ãðí).                                                                  

5.11.2. Åêîíîì³ÿ âèòðàò íà øèíè

                                                                      

Åø = Ñø*àø = 1636,8 (ãðí)

äå:àø - â³äñîòîê åêîíî쳿 âèòðàò íà øèíè ( 5 %.)                                                                     

           

5.11.3. Ïðåì³ÿ çà åêîíîì³þ øèí                                                              

Ïø = àï*Åø = 818,4

äå:àï - â³äñîòîê ïðå쳿 çà åêîíîì³þ øèí,(50 %).                                                            

5.11.4. Âèòðàòè íà øèíè ç óðàõóâàííÿì åêîíî쳿 ³ ïðå쳿                                                                   

Âø = Ñø+Ïø-Å =       31917,6

5.12. Âèòðàòè íà ðåìîíòí³ ìàòåð³àëè:                                                                 

Âðì =     Lçàã*Íðì*Êòð = 35777,7 (ãðí)

                      1000

äå:    Hp ì - íîðìà âèòðàò íà ðåìîíòí³ ìàòåð³àëè íà 1000 KM ïðîá³ãó (45 ãðí)

Êòð = 1,09      

           

5.13. Âèòðàòè íà çàïàñí³ ÷àñòèíè:                                                           

Âç÷ =  Lçàã*Íç÷*Êòð  = 31365,1 (ãðí)

                  1000

 äå:    Hç÷ - íîðìà âèòðàò íà çàïàñí³ ÷àñòèíè íà 1000 KM ïðîá³ãó (39,45 ãðí)

Êòð = 1,09      

                                                                                                                                

5.14. Èíø³ âèòðàòè ìàòåð³àëüíèõ ðåñóðñ³â:                                                                   

̳íø = (Âï+Âìì+Âç÷+Âðì+Âø) * ʳíø = 50410,8 (ãðí)

äå:ʳíø-êîåô³ö³ºíò,ÿêèé âðàõîâóº âèòðàòè íà ³íø³ ìàòåð³àëüí³ ðåñóðñè (0,1)            

5.15. Çàãàëüíà ñóìà ìàòåð³àëüíèõ âèòðàò:                                                                      

ÌÂçàã = Âï+Âìì+Âðì+Âç÷+Âø+̳íø = 504287,9 (ãðí)


6. ÀÌÎÐÒÈÇÀÖ²ÉͲ ²ÄÐÀÕÓÂÀÍÍß ÒÀ                  

ÇÀÃÀËÜÍÎÂÈÐÎÁÍÈײ ÂÈÒÐÀÒÈ                               

Äëÿ ðîçðàõóíêó àìîðòèçàö³éíèõ â³äðàõóâàíü íà ïîâíå â³äíîâëåííÿ îñíîâíèõ ôîíä³â,íåîáõ³äíî âèçíà÷èòè ¿õ âàðò³ñòü.

6.1. Ðîçðàõóíîê âàðòîñò³ ðóõîìîãî ñêëàäó:

                                                                      

Âð.ñ = À³*Âàâò = 2040000 (ãðí)

äå:    Âàâò-áàëàíñîâà âàðò³ñòü àâòîìîá³ëÿ (170000 ãðí);                                                             

                                                                      

6.2. Çàãàëüíà âàðò³ñòü áóä³âåëü , ñïîðóä ³ îáëàäíàííÿ:                                                             

Âá.ñ.î.=Âð.ñ.*(100-Ï) /Ï = 3060000 (ãðí)                                                               

                                                                      

äå: Π -÷àñòêà ðóõîìîãî ñêëàäó ó â³äñîòêàõ â³ä çàãàëüíî¿ âàðòîñò³ îñíîâíèõ âèðîáíè÷èõ ôîíä³â (Ï=40%)

                                                                      

6.3. Âàðò³ñòü áóä³âåëü ³ ñïîðóä:                                                                

 á.ñ.=Âá.ñ.î.*Ïá.ñ./100 = 1836000 (ãðí)                                                                   

äå:                                                                 

Π á.ñ.-÷àñòêà âàðòîñò³ áóä³âåëü ³ ñïîðóä(Ïá.ñ.=60%).                                                                   

                                                          

6.4. Âàðò³ñòü îáëàäíàííÿ:                                                             

                                                                      

 îáë.=Âá.ñ.î*Ïîáë/100 = 1224000 (ãðí)                                                                                                                                         

äå: Π îáë-÷àñòêà âàðòîñò³ îáëàäíàííÿ (Ïîáë.=40%).                                                                     

           

6.5. Ðîçðàõóíîê àìîðòèçàö³éíèõ â³äðàõóâàíü:                                                                      

                                                                      

6.5.1. Íà ïîâíå â³äíîâëåííÿ ðóõîìîãî ñêëàäó:                                                             

Àð.ñ. = Âð.ñ.*Íà ð.ñ = 510000 (ãðí)

äå: Íàð.ñ -    íîðìà àìîðòèçàö³éíèõ â³äðàõóâàíü íà ïîâíå â³äíîâëåííÿ ðóõîìîãî ñêëàäó (Íà³ð.ñ=25%).                                                                  

           

6.5.2. Íà ïîâíå â³äíîâëåííÿ áóä³âåëü ³ ñïîðóä:                                                            

À á.ñ = Â á.ñ*Íàá.ñ /100 = 91800 (ãðí)                                                          

                                                                      

äå:Íà á.ñ  -  íîðìà àìîðòèçàö³éíèõ â³äðàõóâàíü íà ïîâíå â³äíîâëåííÿáóä³âåëü ³ ñïîðóä      (Íà á.ñ=5%).                                                     5         

                                                                      

6.5.3.Ha ïîâíå â³äíîâëåííÿ îáëàäíàííÿ:                                                           

À îáë = Â îáë*Íà îáë/100 = 183600 (ãðí)                                                                  

                                                                      

äå: Íà îáë -    íîðìà àìîðèçàö³éíèõ â³äðàõóâàíü íà ïîâíå â³äíîâëåííÿ îáëàäíàííÿ         (Íàøîáë=15%).

                                                                      

6.6. Âèòðàòè íà ïîòî÷íèé ðåìîíò áóä³âåëü ³ ñïîðóä:                                                               

Âï.ð.á.ñ. = Âîáë* H ï.ð.á.ñ =  55080 (ãðí)

äå: H ï.ð.á.ñ.- ðîçì³ð âèòðàò íà ïîòî÷íèé ðåìîíò áóä³âåëü ³ ñïîðóä (3%).                                 

                                                                      

6.7.Âèòðàòè íà ïîòî÷íèé ðåìîíò îáëàäíàííÿ :                                                             

Âï.ð.îáë = Âîáë* H ï.ð.îáë = 61200 (ãðí)

äå: H ï.ð.îáë- ðîçì³ð âèòðàò íà ïîòî÷íèé ðåìîíò îáëàäíàííÿ(5%).                                                                  

6.8. Ðîçðàõóíîê ñóìè çàãàëüíîâèðîáíè÷èõ âèòðàò:                                                                 

                                                                      

 ç.â.= (ÇÔÇÏ ð.ð.+ ï.ð.îáë+À îáë)* Êç.â.= 356037,8 ( ãðí)                                                             

äå: K ç.â - êîåô³ö³ºíò,ÿêèé âðàõîâóº ³íø³ çàãàëüíîâèðîáíè÷³ âèòðàòè (1,4).                          


7.ÊÀËÜÊÓËßÖ²ß ÑÎÁ²ÂÀÐÒÎÑÒ² ÏÅÐÅÂÅÇÅÍÜ                                                              

Òàáëèöÿ 7.1. Êàëüêóëÿö³ÿ ñîá³âàðòîñò³

Ñòàòò³ âèòðàò Óìîâ ïîçí. Âèòðàòè , ãðí. Ñîá³âàðò³ñòü, ãðí/10 ò.êì; Ñòðóêòóðà, %
1. Çàãàëüíèé ôîíä çàðîá³òíî¿ ïëàòè âî䳿â

ÇÔÇÏâ

164732 0,44 10,3

2. ³äðàõóâàííÿ íà ñîö. çàõîäè â³ä ÇÔÇÏâ

Âñ.ç

63652,4 0,17 3,98
3. Ìàòåð³àëüí³ âèòðàòè:

MB çàã

504287,9 1,35 31,54
- ïàëèâî

Âï

375255,2 1 23,47
- ìàñòèëüí³ ìàòåð³àëè

Bìì

29792,3 0,08 1,86
- â³äíîâëåííÿ çíîñó ³ ðåìîíòó øèí

Âø

31917,6 0,09 2
 - çàïàñí³ ÷àñòèíè

Â3.÷     

31365,1 0,08 1,96
 - ðåìîíòí³ ìàòåð³àëè

Âð.ì

35777,7 0,1 2,24
 - ³íø³ âèòðàòè

³íø

180 0,0004 0,01
4. Àìîðòèçàö³ÿ ðóõ. ñêëàä.

Αð.ñ.

510000 1,37 31,9
5. Çàãàëüâèðîáíè÷³ âèòðàòè

Âç.â.

356037,8 0,95 22,27
Çàãàëüíà ñóìà âèòðàò:

 çàã

1598710,1 4,28 100

7.1. Ñîá³âàðò³ñòü ïåðåâåçåíü;                                            

S 10 òêì=Â çàã*10/Ðð òêì ãðí/10 òêì                                      

7.2.    Ïèòîìà âàãà îêðåìèõ åëåìåíò³â âèòðàò ó çàãàëüí³é ñîá³âàðòîñò³

(âèçíà÷àºòüñÿ ç òî÷í³ñòþ äî 0,01):            

Ïâ1=ÇÔÇÏâ / Â çàã*100(%);              

Ïâ2= Âñ.ç/Âçàã* 100(%).                                             


8. Ô²ÍÀÍÑβ ÏÎÊÀÇÍÈÊÈ                                   

                                                                      

8.1.Ðîçðàõóíîê äîõîä³â â³ä  ïåðåâåçåíü:                                                 

8.1.1. Ðîçðàõóíîê äîõîä³â â³ä âàíòàæíèõ ïåðåâåçåíü:

                                                                      

Äïåð = Qð*t =  2400678 (ãðí)

äå:    t - äîãîâîðíèé òàðèô çà îäíó òîíó ïåðåâåçåíîãî âàíòàæó, ãðí

t = Çîáù*1,5/Qð = 13,6 (ãðí   )

8.1.2. Äîõîä çà åêñïåäèðóâàííÿ âàíòàæó                                                           

                                                                      

Äñêñ =  Äïåð *àåêñ = 72020,3  (ãðí),                                                              

                                                                      

äå:   Çåêñ - â³äñîòîê íàäáàâêè çà åêñïåäèðóâàííÿ âàíòàæó (3%).                                                                   

8.1.3. Çàãàëüíà ñóìà äîõîä³â                                                                     

                                                                      

Äçàã = Äïåð + Äåêñ = 2472698  (ãðí)

8.3. Äîõ³äíà ñòàâêà:                                                           

                                                                      

d = Äçàã*10/Ðð = 6,6 (ãðí/10 ò.êì;ãðí)                                                                   

                                                                      

8.4. Çàãàëüíèé ïðèáóòîê:                                                              

                                                                      

Ïçàã =  Äçàã – Âçàã – ÏÄÂ – Âàäì = 159129 (ãðí)

äå:ÏÄ - ïîäàòîê íà äîäàòêîâó âàðò³ñòü,                                                           

                                                                      

ÏÄÂ = Ñïäâ * Äçàã =  494540 (ãðí)                                                                                                                                    

äå:    Ñïäâ - ñòàâêà ïîäàòêó íà äîäàòêîâó âàðò³ñòü,Ñïäâ = 20%;  

                                                                      

Âàäì - âèòðàòè àäì³í³ñòðàòèâí³:

                                                                      

Âàäì =(ÇÔÇÏ êåð.+À á.ñ.+Âï.ð.á.ñ.) * Êàäì  = 220320 (ãðí),

äå:    Êàäì - êîåô³ö³ºíò,ÿêèé âðàõîâóº ³íø³ àäì³í³ñòðàòèâí³ âèòðàòè(1,5).

 8.5. ×èñòèé ïðèáóòîê                                                                   

                                                                      

Ï÷èñ = Ïçàã-Âá-Ïç = 109539 (ãðí),                                                                                                                                     

äå:Âá - â³äðàõóâàííÿ â áþäæåò,                                                                

Âá = ae * Ïçàã = 47738,6 (ãðí);                                                                                                                                           

äå-àá - â³äñîòîê â³äðàõóâàíü ó áþäæåò, (30 %);                                                                          

ïç - ïîäàòîê íà çåìëþ                                                                    

ïç = Fà* 1,1 *Ai*Cíç*nìec = 1851,4 (ãpH),                                                                          

äå:    Fà - ïëîùà àâòîìîá³ëÿ,                                                                      

                                                                      

Fà = à * ó = 18,5875(ì2) ,

äå: à - äîâæèíà àâòîìîá³ëÿ, (7435 ì);

ó - øèðèíà àâòîìîá³ëÿ,(2500 ì);                                                                                                 

1,1 - êîåô³ö³ºíò, ùî âðàõîâóº â³äñòàíü ì³æ àâòîìîá³ëÿìè ï³ä ÷àñ                                          

ñòîÿíêè íà òåðèòî𳿠ÀÒÏ;                                                           

Ñíç - ñòàâêà ïîäàòêó íà çåìëþ, (0,6288 ãðí/ì2).                                                            

                                                          

8.6. Ðîçïîä³ë ïðèáóòêó ÷èñòîãî:                                                              

                                                                      

-   ôîíä ðîçâèòêó âèðîáíèöòâà                                                                

                                                                      

ÔÐÂ= àôðï * Ï÷èñ = 33957 (ãðí),                                                                                                                                       

äå: àôðï - â³äñîòîê ôîíäó ðîçâèòêó âèðîáíèöòâà, (31 %);                                                                                                                               

-   ôîíä ñîö³àëüíîãî ðîçâèòêó                                                                  

ÔÑÐ = àôñð * Ï÷èñ = 29575,4 (ãðí)                                                                                                                                    

äå: àôåð - â³äñîòîê ôîíäó ñîö³àëüíîãî ðîçâèòêó,(27) %;                                                            

-   ôîíä çàîõî÷óâàííÿ:                                                                   

                                                                      

ÔÇ = àôç * Ï÷èñ = 29575,4 (ãðí)                                                                 

                                                                      

äå:àôï - â³äñîòîê ôîíäó çàîõî÷åííÿ, àôï = 27%;                                                              

                                              

-öåíòðàë³çîâàíèé ôîíä:                                                                

ÖÔ = àöô * Ï÷èñ = 10953,9 (ãðí)                                                                                                                                       

àöô - â³äñîòîê öåíòðàë³çîâàíîãî ôîíäó,(10 %);                                                              

                                  

- ðåçåðâíèé ôîíä

                                                                      

ÔÐ = àôð * Ï÷èñ 5476,93 (ãðí)                                                                                                                               

äå: àôð - â³äñîòîê ðåçåðâíîãî ôîíäó,(5 %).           

                                                                      

8.7. гâí³ ðåíòàáåëüíîñò³                                                            

                                                                      

8.7.1. Ðåíòàáåëüí³ñòü ïåðåâåçåíü                                                             

                                                                      

R = Ïçàã/Âçàã*100 = 10 %.                                                                

                                                                      

8.7.2. Ðåíòàáåëüí³ñòü âèðîáíè÷èõ ôîíä³â:                                                                     

                                                                      

Râô = Ïçàã/Âîâô*100 = 3,1%.                                                           

                                                                      

äå: Âîâô- âàðò³ñòü îñíîâíèõ âèðîáíè÷èõ ôîíä³â:                                                                      

 îâô=  ð.ñ.+ á.ñ+ îáë = 5100000 (ãðí).                                                                                                                         

8.7.3. Ðåíòàáåëüí³ñòü ïî ÷èñòîìó ïðèáóòêó                                                                   

                                                                      

R÷èñ= Π ÷èñ / çàã *100 =       6,9%.                                                 

                                                                      

8.8. Åôåêòèâí³ñòü âèêîðèñòàííÿ îñíîâíèõ âèðîáíè÷èõ ôîíä³â                                                                                                                                      

8.8.1. Ôîíäîâ³ääà÷à                                                           

                                                                      

ÔÂ= Äçàã/Âîâô = 0,48 (ãðí äîõ/ãðí îâô)                                                                                                                                     

8.8.2. Ôîíäîéîìê³ñòü                                                                    

                                                                      

ÔÅ= 1/ÔÂ = 2,08 (ãðí îôâ/ãðí äîõ)                                                          

                                                                      

8.8.3. Ôîíäîâîîçáðîºíí³ñòü                                                                     

                                                                      

ÔÎ=Âîâô/ N ïåð = 164516,13 (ãðí äîõ/ãðí îâô)                                         


9. Ô²ÍÀÍÑÎÂÀ ÑÒ²ÉʲÑÒÜ ÀÒÏ

9.1. Ðåçóëüòàòè ðîçðàõóíê³â ïîðîãà ðåíòàáåëüíîñò³ ³ çàïàñó ô³íàíñîâî¿                    

ñò³éêîñò³ çâîäèìî â òàáëèö³ 9.1.               

                       

Òàáëèöÿ 9.1. Ðîçðàõóíîê ïîðîãà ðåíòàáåëüíîñò³ ³ çàïàñó ô³íàíñîâî¿ ñò³éêîñò³

Íàéìåíóâàííÿ ïîêàçíèê³â Ïîçíà÷åííÿ Çíà÷åííÿ
1. Äîõîäè ÷èñò³, ãðí

Ä÷èñ

1978158,672
2. Ïðèáóòîê, ãðí

Ïçàã

159128,572
3. Âèòðàòè ïåðåì³íí³, ãðí

Âïåð

1201795,4
4. Âèòðàòè ïîñò³éí³, ãðí

Âïîñ

667465,5
5. ×àñòêà ìàðæèíàëüíîãî äîõîäó ó âèïóñêó,%

Àìä

41,79
6. Ìàðæèíàëüíèé äîõîä, ãðí

Äì

826594,072
7. Ïîð³ã ðåíòàáåëüíîñò³, ãðí ÏR 1597189,5
8. Çàïàñ ô³íàíñîâî¿ ñò³éêîñò³ -   ãðí -   %

ÔÇÓãðí                     

380969,172
ÔÇÓ% 23,85

9.2. Äîõîäè ÷èñò³                

                       

Ä÷èñ =  Äçàã - ÏÄ 1978158,67 (ãðí)                       

                       

9.3.    Âèòðàòè ïåðåì³íí³                

                       

Çïåð = Bç÷ + Âðì + Âï + Bìì + Âø + Àð.ñ + ÇÔÇÏâ+̳íø = 1201795,4 (ãðí)                   

                       

9.4. Âèòðàòè ïîñò³éí³                     

                       

Âïîñò = Âàäì + Âñ.3. + Â ç.â. +Âìç =  667465,5 (ãðí)                                      

                       

9.5. Ìàðæèíàëüíèé äîõîä             

                       

Äì = Bïîñò +     Ïçàã = 826594,07 (ãðí)

                       

9.6. ×àñòêà ìàðæèíàëüíîãî äîõîäó                      

                       

Àì.ä. = Äì/Ä÷èñ*100% =  41,79%

                       

9.7.   Ïîð³ã ðåíòàáåëüíîñò³            

                       

ÏR = Âïîñò/Àìä * 100 (ãðí) = 1597189,5 (ãðí)

                       

9.8.    Çàïàñ ô³íàíñîâî¿ ñò³éêîñò³:             

-   ó ãðèâíÿõ             

                       

ÇÔÓãðí = Ä÷èñ-ÏR =380969,17 (ãðí)

                       

-   ó â³äñîòêàõ                       

                       

ÇÔÓ%= Ä÷èñ-ÏR *100 = 23,85%

                  Ä÷èñ

           

9.9.    Ãðàô³÷íå çîáðàæåííÿ ô³íàíñîâî¿ ñò³éêîñò³                                  

                       

Ãðàô³÷íå çîáðàæåííÿ ô³íàíñîâî¿ ñò³éêîñò³ ïîêàçàíî â äîäàòêó ¹1.


10.   ÅÊÎÍÎ̲×ÍÀ ÅÔÅÊÒÈÂͲÑÒÜ 

10.1. Åêîíîì³÷íà åôåêòèâí³ñòü ïðîåêòó

10.1.1. Ïðîäóêòèâí³ñòü ïðàö³ â íàòóðàëüíèõ ïîêàçíèêàõ                                                                   

                                                                      

ÏÒòí = Qð/Nâ = 7731,7 (ò/1â)

ÏÒòêìí = Ðð/Nâ = 162365 (ò.êì/1â)

10.1.2. Ïðîäóêòèâí³ñòü ïðàö³ â ãðîøîâèõ ïîêàçíèêàõ                                                            

ÏÒãðí =Äçàã/     Nâ = 107509 (ãðí/1â)

10.2. Åêîíîì³÷íà åôåêòèâí³ñòü ïåðåâåçåíü                                                                    

                                                                      

à) Çíèæåííÿ ñîá³âàðòîñò³ â³ä çì³íè êîåô³ö³ºíòà âèêîðèñòàííÿ ïðîá³ãó β .                                                               

Ï%β =  βïð      *100%= 104,92

              βàòï                                       

 βàòï      = 0,61

 

+ΔS% = (     100              -1 )*100 =  -5,83%

                  Ï%β* δ

δ - êîåô³ö³ºíò íåïðîïîðö³éíîñò³                                                             

 δ =  lâ¿+ βàòï*Vò*tí-ð   = 0,988

         lâ¿+ βïð*Vò*tí-ð                                                 

                                                                                                                                             

                                                                      

á) Âàíòàæîîá³ã ïî ΑΤΉ

                                                                      

Ðàòï = Ðð.ïð*     βïð       = 3559339(ò.êì)

                        βàòï

                                              

ΔΡ = Ðð.ïð - ÐÀÒÏ = 175049,42  (ò.êì)                                                                  

                                              

â) Âïëèâ çì³íè:                                                                  

                                                                      

-   âàíòàæîîá³ãó íà ïðèáóòîê                                                                   

                                                                      

± ΔΠ ð  = ΔΡ*(0,8*dàòï-Sàòï) =18850,74(ãðí)

                             10

äå:

dàòï - äîõ³äíà ñòàâêà ïî ÀÒÏ

                                                                      

dàòï =    dïð*100     =  7,00 (ãðí/10òêì)

               100+ ΔS%  

Sàòï – ñîá³âàðò³ñòü ïî ÀÒÏ                                     

                                                                      

                                                                      

                                                                      

- ñîá³âàðò³ñòü ïî ÀÒÏ. Ç îãëÿäó íà, ùî ñîá³âàðò³ñòü                                                                 

çìåíøèëàñÿ íà 2%, òîáòî                                                              

Sàòï =Sïð*105,82 =      4,53 (ãðí/10ò.êì)                                                                

                                                                      

-   ñîá³âàðòîñò³ íà ïðèáóòîê                                                                     

± ΔΠs =  Ρð.ïð*(Sàòï - Sïð)   = 23227 (ãðí)

                             10                         

-   äîõ³äíî¿ ñòàâêè íà ïðèáóòîê                                                               

± ΔΠð =   ΔΡ*(0.8*dàòï-Sàòï)   = 18850,74 (ãðí)

                               10

ã) Çàãàëüíèé âïëèâ çì³í                                                               

                                                                      

Σ± ΔΠp.s.d. = ΔΠp + ΔΠs + ΔΠd  = 60928,5 (ãðí)                                                              


11.ÒÅÕͲÊÎ-ÅÊÎÍÎ̲×Ͳ ÏÎÊÀÇÍÈÊÈ

Òàáëèöÿ 11.1. Òåõí³êî-åêîíîì³÷í³ ïîêàçíèêè

Ïîêàçíèêè Îäèíèö³ Âèì³ðþâàííÿ Çíà÷åííÿ
1. Îáñÿã ïåðåâåçåíü T. 177828
2. Âàíòàæîîá³ã ò.êì 3734388
3. ×èñåëüí³ñòü âî䳿â ÷îë. 23
4. Ôîíä îïëàòè ïðàö³ ãðí. 164732
5. ³äðàõóâàííÿ íà ñîö³àëüí³ çàõîäè ãðí. 63652,4
6. Ñåðåäíüîì³ñÿ÷íà çàðîá³òíà ïëàòà âî䳿â ãðí. 497,4
7. Çàãàëüíà ñóìà âèòðàò ãðí. 1598710,1
8. Ñîá³âàðò³ñòü 10 ò.êì ãðí/Þò.êì 4,28
9. Çàãàëüíà ñóìà äîõîä³â ãðí. 2472698,34
10. Äîõ³äíà ñòàâêà 10 ò.êì ãðí/Þò.êì 6,6
11. Áàëàíñîâèé ïðèáóòîê ãðí. 667465,5
12. ×èñòèé ïðèáóòîê ãðí. 1978158,672
13. Ðåíòàáåëüí³ñòü % 10
14. Åêîíîì³÷íà åôåêòèâí³ñòü ãðí. 60928,5

 
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